Robert Jackson
262e9b1e86
fix(scala): Mark (lambda_expression) without bindings as @defintition.parameters
...
When you have a lambda expression like:
```scala
val fruits = List("apple", "banana", "avocado", "papaya")
val countsToFruits = fruits.groupBy(fruit => fruit.count(_ == 'a'))
for ((count, fruits) <- countsToFruits) {
println(s"with (fruits) 'a' × $count = $fruits")
}
```
The `fruit => fruit.count(_ == 'a')` lambda expression (note: without
wrapping parenthesis) does not create a `(binding)` node. Its syntax
tree is:
```
(lambda_expression) ; [5:18 - 47]
parameters: (identifier) ; [5:18 - 22]
(call_expression) ; [5:27 - 47]
function: (field_expression) ; [5:27 - 37]
value: (identifier) ; [5:27 - 31]
field: (identifier) ; [5:33 - 37]
arguments: (arguments) ; [5:38 - 47]
(infix_expression) ; [5:39 - 46]
left: (wildcard) ; [5:39 - 39]
operator: (operator_identifier) ; [5:41 - 42]
right: (character_literal) ; [5:44 - 46]
```
That example just _happens_ to be **exactly** one of the example from
https://www.scala-lang.org/ ([see
playground](https://scastie.scala-lang.org/S0bkCiXkQiuOMXnlhWn46g )) 😁 .
2023-10-15 14:33:21 -04:00
